The conversion truncates; that is, the fractional part Not just affecting the output visually.To subscribe to this RSS feed, copy and paste this URL into your RSS reader.

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My purpose was to provide the minimal implementation of round which could function even on old Intel P3 or P4 families from 2000's.P3 doesn't even have SSE2, so the compiler will already be using x87 for Didn't you mean pow(10,place) rather than the binary operator ^ in 10^place? It's good to know when to pick which, too.There are indeed different rounding algorithms which can all make reasonable claims to being "correct".

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I observed the most compact code on GPUs, where I use the following implementation of round in asm for x86 architecture and MS VS specific C++:Best way to rounding off a floating value by "n" decimal places, is as following with in O(1) time:-We have to round off the value by 3 places i.e. is discarded.

Is it because the tie is resolved away from zero rather than to nearest even?Note: the C spec says "rounding halfway cases away from zero, regardless of the current rounding direction. The Overflow Blog It has 6 decimal digits of precision. This question was asked and answered in another time when life was hard and the joys were few. Featured on Meta

Especially on non-Windows, where the standard calling convention has no call-preserved registers, so the compiler can't keep any FP values in XMM registers across a On x86, an FP->integer conversion that overflows the integer produces The below is functionally equivalent, as far as I can tell, but clocks in at Among the reasons for the better performance is the skipped branching.There is no need to implement anything, so I'm not sure why so many answers involve defines, functions, or methods.We have the following and and header for type-generic macros.If you cannot compile this, you have probably left out the math library. Another niche: @chux interesting, and IEEE 754-2008 standard does specify that rounding preserves signs of zeros and infinities (see 5.9). I found that adding the long double literal suffix to my constants fixed your example issue, but I don't know if there are other precision examples that it wouldn't catch.btw if you add 0.49999999999999994 instead of 0.5, it does work ok for both 0.49999999999999994 and 5000000000000001.0 as input.

First Method:- Using Float precision It also throws an error in debug mode if the value is out of range of the integer type, thereby serving roughly as a viable library function.As pointed out in comments and other answers, the ISO C++ standard library did not add This leads to the compact code below. For example, 5.567 should become 5.57 and 5.534 should become 5.53. Stack Overflow for Teams is a private, secure spot for you and See this post for details: Boost also offers a set of simple rounding functions; see my answer.Unless your compiler int size defaults to 1024 bits, this ain't gonna be accurate for huge double...I think that is acceptable given when it will be used: If your double value is 1.0 e+19, rounding out to 3 places doesn't make sense.sure, but the question is for a generic round, and you can't control how it will be used. If num is positive then add 0.5. If decimal value is from “.6 to.9″, it returns the … If decimal value is from ”.1 to.5″, it returns integer value less than the argument. We can see this from the draft C++ standard section A prvalue of a floating point type can be converted to a prvalue of an Round to nearest. The following is an implementation of The probable reason there is no round function in the C++98 standard library is that it can in fact be implemented in different ways.

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